# Comments on From Diophantus to Fermat

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## Sivasubramaniam Sivakumar said:

Nice!

I would never thought of this:

This is of the form $$2(3a^2b + b^3)$$ where $$a = y$$ and $$b = 3.$$ Now $$2(3a^2b + b^3) = (a + b)^3 - (a - b)^3.$$
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